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Adrian Ţepeş May 25th, 2012 05:59 PM

Rep to whoever can solve this
 
http://upload.wikimedia.org/wikipedi...f5c83b2d88.png
































http://files.sharenator.com/92_what_...173187-535.jpg

Schofield May 25th, 2012 06:25 PM

Re: Rep to whoever can solve this
 
0

S.T.A.L.K.E.R. May 25th, 2012 06:49 PM

Re: Rep to whoever can solve this
 
Pi












Mmm... Pie

Arld May 25th, 2012 07:10 PM

Re: Rep to whoever can solve this
 
I'll solve that for you, if you can solve an issue I've been unable to... solve:

It's related to number theory. So basically, my question is whether for every natural number N there is an existent & associated positive integer I, so that every natural number (N) is the sum of at most I*K^N powers of the natural numbers.

Little help:

http://upload.wikimedia.org/wikipedi...cf5d7a8d92.png

Totes May 25th, 2012 07:32 PM

Re: Rep to whoever can solve this
 
Chuck Norris.

Adrian Ţepeş May 25th, 2012 07:37 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by GraemerS (Post 5641514)
I'll solve that for you, if you can solve an issue I've been unable to... solve:

It's related to number theory. So basically, my question is whether for every natural number N there is an existent & associated positive integer I, so that every natural number (N) is the sum of at most I*K^N powers of the natural numbers.

Little help:

http://upload.wikimedia.org/wikipedi...cf5d7a8d92.png

vT denotes the transpose of v, α(v) = 1/γ(v), and P(v) denotes the projection onto the direction of v.

Lindale May 25th, 2012 10:33 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by computernerd (Post 5641503)


Ah yes. Spacial relativity, or more specifically, the
Lorentz transformation! :nodding:

where vT denotes the transpose of v, α(v) = 1/γ(v), and P(v) denotes the projection onto the direction of v. :nodding:

Adrian Ţepeş May 25th, 2012 11:41 PM

Re: Rep to whoever can solve this
 
Indeed.

I'm also good at Nuclear Engineering. Which you know is the branch of engineering concerned with the application of the breakdown (fission) as well as the fusion of atomic nuclei and/or the application of other sub-atomic physics, based on the principles of nuclear physics.

Silberio May 26th, 2012 12:50 AM

Re: Rep to whoever can solve this
 

Lindale May 26th, 2012 01:38 AM

Re: Rep to whoever can solve this
 
The sciences are what make life work, especially the complex quantum physics required to make beer! :nodding:

Totes May 26th, 2012 08:11 AM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by Master Lindale Mustaparta (Post 5641538)
The sciences are what make life work, especially the complex quantum physics required to make beer! :nodding:

I thought that was the Irish.

Silberio May 26th, 2012 01:35 PM

Re: Rep to whoever can solve this
 
Nein, ze German beer companies dissaproves.

Lindale May 26th, 2012 02:50 PM

Re: Rep to whoever can solve this
 
:agreed

Schofield May 26th, 2012 03:05 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by Einherjar Silberio (Post 5641633)
Nein, ze German beer companies dissaproves.

So much so, that German Beer companies forgot how to spell 'disapprove' correctly. :cort:

Red Menace May 26th, 2012 03:32 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by Einherjar Silberio (Post 5641534)

^

Silberio May 26th, 2012 03:34 PM

Re: Rep to whoever can solve this
 
Ze grammar is not important right nao! But ze bier is... Bier, bier, bier!

Schofield May 26th, 2012 04:41 PM

Re: Rep to whoever can solve this
 
You're speaking in German, or pretending to, and saying grammar is not important?

OUT..

Silberio May 26th, 2012 05:05 PM

Re: Rep to whoever can solve this
 
Nein, besser du läufst jetzt. LOS, RAUS.

Totes May 26th, 2012 05:11 PM

Re: Rep to whoever can solve this
 
Guise. Alcohol is never the answer. But it does make you forget the question!

Commissar MercZ May 26th, 2012 10:30 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by GraemerS (Post 5641514)
I'll solve that for you, if you can solve an issue I've been unable to... solve:

It's related to number theory. So basically, my question is whether for every natural number N there is an existent & associated positive integer I, so that every natural number (N) is the sum of at most I*K^N powers of the natural numbers.

Little help:

http://upload.wikimedia.org/wikipedi...cf5d7a8d92.png

Quote:

Originally Posted by computernerd (Post 5641520)
vT denotes the transpose of v, α(v) = 1/γ(v), and P(v) denotes the projection onto the direction of v.

Quote:

Originally Posted by Master Lindale Mustaparta (Post 5641526)

Ah yes. Spacial relativity, or more specifically, the
Lorentz transformation! :nodding:

where vT denotes the transpose of v, α(v) = 1/γ(v), and P(v) denotes the projection onto the direction of v. :nodding:

Quote:

Originally Posted by computernerd (Post 5641529)
Indeed.

I'm also good at Nuclear Engineering. Which you know is the branch of engineering concerned with the application of the breakdown (fission) as well as the fusion of atomic nuclei and/or the application of other sub-atomic physics, based on the principles of nuclear physics.


Biiviz May 27th, 2012 03:42 AM

Re: Rep to whoever can solve this
 
Related.

http://i.imgur.com/5SlL6.gif

Silberio May 27th, 2012 05:20 AM

Re: Rep to whoever can solve this
 

Nemmerle May 27th, 2012 11:49 AM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by computernerd (Post 5641503)

For what?

Edit: Also, I really thought this was going to be that poorly phrased equation where it wasn't clear whether you were meant to multiply first or not that was going around a while back.

Adrian Ţepeş May 27th, 2012 12:23 PM

Re: Rep to whoever can solve this
 
Quote:

Originally Posted by Biiviz (Post 5641732)

Yep, there it goes. Any shred of sanity I once had, it's now gone.


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